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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 2: Basic components and Electric Circuits"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.1: Power.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Example 2.1\n",
"//Computation of power absorbed by each part\n",
"//From figure 2.13a\n",
"V=2;I=3;\n",
"//We have Power(P)=V*I\n",
"P=V*I\n",
"printf('a) Power =%dW\n',P)\n",
"if P>0 then\n",
" printf('Power is absorbed by the element\n')\n",
"else\n",
" printf('Power is supplied by the element\n');\n",
"end \n",
"\n",
"clear P;\n",
"//From figure 2.13b\n",
"V=-2;I=-3;\n",
"//We have Power(P)=V*I\n",
"P=V*I\n",
"printf('b) Power =%dW\n',P)\n",
"if P>0 then\n",
" printf('Power is absorbed by the element\n')\n",
"else\n",
" printf('Power is supplied by the element\n')\n",
"end\n",
"\n",
"//From figure 2.13c\n",
"V=4;I=-5;\n",
"//We have Power(P)=V*I\n",
"P=V*I\n",
"printf('c) Power =%dW\n',P)\n",
"if P>0 then\n",
" printf('Power is absorbed by the element\n')\n",
"else\n",
" printf('Power is supplied by the element\n')\n",
"end "
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.2: Dependent_sources.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Example 2.2\n",
"//Calculate vL \n",
"disp('Given')\n",
"disp('v2=3V')\n",
"v2=3;\n",
"//From figure 2.19b\n",
"disp('Considering the right hand part of the circuit ')\n",
"disp('vL=5v2')\n",
"vL=5*v2;\n",
"disp('On substitution')\n",
"printf('vL=%dV\n',vL);\n",
""
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.3: Ohm_law.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Example 2.3\n",
"//Calculate the voltage and power dissipated acreoss the resistor terminals\n",
"//From figure 2.24b\n",
"disp('Given')\n",
"disp('R=560 ohm ; i=428mA')\n",
"R=560;i=428*10^-3;\n",
"//Voltage across a resistor is\n",
"disp('v=R*i')\n",
"v=R*i;\n",
"printf('Voltage across a resistor=%3.3fV\n',v)\n",
"\n",
"//Power dissipated by the resistor is\n",
"disp('p=v*i')\n",
"p=v*i;\n",
"printf('Power dissipated by the resistor=%3.3fW\n',p)"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 2.4: Ohm_law.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Example 2.4\n",
"//Calculate the power dissipated within the wire\n",
"//From figure 2.27\n",
"disp('Given')\n",
"disp('Total length of the wire is 4000 feet')\n",
"disp('Current drawn by lamp is 100A')\n",
"//Considering American Wire Gauge system(AWG)\n",
"//Referring Table 2.4\n",
"disp('4AWG=0.2485ohms/1000ft')\n",
"l=4000; i=100 ; rl=0.2485/1000;\n",
"//Let R be the wire resistance\n",
"R=l*rl;\n",
"//Let p be the power dissipated within the wire\n",
"disp('p=i^2*R')\n",
"p=i^2*R\n",
"printf('Power dissipated within the wire=%dW\n',p)"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
