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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 24: UNIT COMMITMENT"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 24.3: Priority_List_Method.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"// Priority List Method \n",
"clear\n",
"clc;\n",
"Fc1=1.1;//Fuel cost(1)=Rs 1.1/MBtu\n",
"Fc2=1;//Fuel cost(2)=1/MBtu\n",
"Fc3=1.2;//Fuel cost(3)=1.2/MBtu\n",
"P1max=600;\n",
"P1=P1max;\n",
"F1=600+7.1*P1+0.00141*(P1^2);//For P1= Pm1ax\n",
"Favg1=F1*Fc1/600;//Full load average production cost\n",
"P2max=450;\n",
"P2=P2max;\n",
"F2=350+7.8*P2+0.00195*(P2^2);//For P2= P2max\n",
"Favg2=F2*Fc2/450;//Full load average production cost\n",
"P3max=250;\n",
"P3=P3max;\n",
"F3=80+8*P3+0.0049*(P3^2);//For P3= P3max\n",
"Favg3=F3*Fc3/250;//Full load average production cost\n",
"mprintf('Priority List is as follows\n');\n",
"mprintf('Unit Rs/MWhr MinMW Max MW\n')\n",
"mprintf(' 2 %.3f 100 %.0f \n',Favg2,P2max)\n",
"mprintf(' 1 %.4f 60 %.0f \n',Favg1,P1max)\n",
"mprintf(' 3 %.2f 50 %.0f \n\n',Favg3,P3max)\n",
"Fmax1=P1max+P2max+P3max;\n",
"Fmax2=P2max+P1max\n",
"Fmax3=P2max\n",
"mprintf('Unit Commitment Scheme is follows\n')\n",
"mprintf('Combination Min.MW from Combination Max.MW from Combination\n');\n",
"mprintf('2+1+3 310 %.0f \n',Fmax1);\n",
"mprintf('2+1 260 %.0f \n',Fmax2);\n",
"mprintf('2 100 %.0f ',Fmax3);"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 24.4: illustrate_the_dynamic_programming_for_preparing_an_optimal_unit_commitment.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"// illustrate the dynamic programming for preparing an optimal unit commitment.\n",
"\n",
"clear\n",
"clc;\n",
"function[F1]=F1(P1)\n",
" F1=7.1*P1+.00141*(P1^2)\n",
" mprintf('F1(%.0f)=%.1f\n',P1,F1);\n",
"endfunction\n",
"function[f2]=f2(P2)\n",
" f2=7.8*P2+.00195*(P2^2)\n",
" mprintf('f2(%.0f)=%.0f\n',P2,f2);\n",
"endfunction\n",
"function[F]=F(P1,P2)\n",
" F1=7.1*P1+.00141*(P1^2)\n",
" F2=7.8*P2+.00195*(P2^2)\n",
" F=F1+F2\n",
" mprintf('F1(%.0f)+f2(%.0f)=%.0f\n',P1,P2,F);\n",
" endfunction\n",
"P1max=600;\n",
"P2max=450;\n",
"mprintf('Unit Commitment using Load 500MW\n')\n",
"F1(500);\n",
"mprintf('Since min. Power of second unit is 100MW , we find\n');\n",
"F(400,100);\n",
"F(380,120);\n",
"F(360,140);\n",
"mprintf('Therefore for load 500 MW , the load commitment on unit 1 is 400 MW and that on 2 is 100 MW which gives min. cost\n');\n",
"mprintf('Next we increase the load by 50 MW and loading unit 1 we get, \n');\n",
"F1(550);\n",
"mprintf('Also if we distribute a part of load to unit 2 we get ,\n')\n",
"F(450,100);\n",
"F(400,150);\n",
"F(350,200);\n",
"mprintf('Therefore for load 550 MW , the load commitment on unit 1 is 400 MW and that on 2 is 150 MW which gives min. cost\n');\n",
"\n",
"\n",
""
]
}
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{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
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