1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
|
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 20: LOAD FREQUENCY CONTROL"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 20.1: EX20_1.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"//Determine the load taken by the set C and indicate the direction in which the energy is flowing\n",
"clear \n",
"clc;\n",
"//let x MW flows from A to B\n",
"//Load on station A=75+x\n",
"//%drop in speed =5*(75+x)/200\n",
"//load on station B =(30-x)\n",
"//%drp in speed=(30-x)*4/75\n",
"x=(1.6-1.875)/(.025+.12+.0533);//by manipulating equation : 5*(75+x)/200 + 3*x/25 =(30-x)*4/75 \n",
"mprintf('x=%.2f MW\n',x);\n",
"mprintf('which means power of magnitude %.2f MW will be from B to A',abs(x));"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 20.2: Determine_the_load_shared_by_each_machine.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"// Determine the load shared by each machine .\n",
"clear\n",
"clc;\n",
"//Let x be the power supplied by 110 MW unit\n",
"// the percent drop in speed = 5x/110\n",
"x=(250*11)/(21+11);// by manipulating equation : 5x/110=5x(250-x)/210\n",
"P=250-x;//Power shared by 210 MW unit \n",
"mprintf('Power supplied by 210 MW unit = %.2f MW \n',P);"
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 20.3: EX20_3.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"// Determine the frequency to which the generated voltage drops before the steam flow commences to increase to meet the new load\n",
"clear \n",
"clc;\n",
"E=4.5*100;//Energy stored at no load(MJ)\n",
"E1=25*.6;//Energy lost by rotor(MJ)\n",
"fnew=sqrt((E-E1)/E)*50;\n",
"mprintf('new frequency will be %.2f Hz',fnew);"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|