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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 14: Extraction"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 14.3_1: Length_required.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"clc\n",
"//initialization of variables\n",
"Rat1 = (6.5/3)*(1-0.47)// as Rat = x0/y0\n",
"m = 0.14 \n",
"H = (6.5*10^3)/3600 // Extract flow in g/sec\n",
"L = (3*10^3)/3600// Solvent flow in g/sec\n",
"d= 10 // cm\n",
"A = 0.25*%pi*d^2 // cm^2\n",
"l = 65 // cm\n",
"//Calculations and Results\n",
"Kya = ((H/(l*A))*(1/(1-((m*H)/L)))*(log((1-0.14*Rat1)/(0.47))))*10^3// kg/m^3-sec\n",
"printf('The value of Kya is %.2f kg/m^3-sec',Kya)\n",
"Rat2 = (6.5/3)*(1-0.1)//For case B\n",
"l2 = l*(log(1/((1-0.14*Rat2)/(0.1))))/(log(1/((1-0.14*Rat1)/(0.47))))/100// m\n",
"printf('\nThe length for 90 percent recovery is %.1f m',l2)\n",
""
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 14.4_1: No_of_stages_required.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"\n",
"clc\n",
"//Initialization of variables\n",
"m = 0.018 \n",
"H = 450 // litres/hr\n",
"L = 37 // litres/hr\n",
"Ynplus1byY1 = 100 \n",
"//Calculations\n",
"E =m*H/L\n",
"nplus1 = log((Ynplus1byY1*((1/E)-1))+1)/log(1/E)\n",
"n = nplus1 -1\n",
"printf('The number of ideal stages are %.f',n)\n",
"N = 0.60//Murphree efficienct\n",
"E1 = (m*H/L) + (1/N) - 1\n",
"nplus1 = log((Ynplus1byY1*((1/E1)-1))+1)/log(1/E1)\n",
"n=nplus1-1\n",
"printf('\nThe number of stages required if Murphree efficiency is 60 percent is %.f',n)\n",
""
]
}
,
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 14.5_1: No_of_stages_including_feed.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"clc\n",
"//initialization of variables\n",
"F = 5 //kg feed\n",
"S = 2 // kg solvent\n",
"E = F-S // kg extract\n",
"W = 1 // kg waste\n",
"EG = 80 // ppm\n",
"y0 = (100-99)/100 // mole fraction of gold left\n",
"y1 = y0*EG*W/S // concentration in raffinate\n",
"//Calculations\n",
"xN = (EG*W - y1*S)/E // solvent concentration\n",
"xNminus1 = ((xN*(E+S)) - EG*W)/F//feed stage balance\n",
"N = 1 + ((log((xN-xNminus1)/(y1))/log(F/S)))//numner of stages including feed stage\n",
"//Results\n",
"printf('The number of stages including feed stage is %.f',N)"
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
