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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Chapter 1: Basics"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## Example 1.1: Neutral_temperature.sce"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {
"collapsed": true
},
"outputs": [],
"source": [
"clc\n",
"clear\n",
"//input\n",
"x=(0:50:550)//temperature difference in x axis\n",
"y=[0,0.43,0.79,1.10,1.36,1.54,1.69,1.77,1.80,1.78,1.70,1.54]//emf in y axis\n",
"//calculation\n",
"title('a graph of E vs teta')//setting title for graph\n",
"xlabel('temperature difference teta')//setting x label\n",
"ylabel('emf E')//setting y label\n",
"plot(x,y)//plotting the graph\n",
"printf('from the grapgh it can be determined that neutral temperature is 400deg C')\n",
"x=(50:50:550)//temperature difference in x axis\n",
"y=[8.6,7.9,7.3,6.8,6.2,5.6,5.1,4.5,4.0,3.4,2.8] //E/theta in y axis\n",
"plot(x,y,'+-')//plotting the graph\n",
"title('a graph of E/teta vs teta')//set title\n",
"xlabel('temperature difference teta')//set x label\n",
"ylabel(' E/teta')//set y label\n",
"legend('E Vs Theta','E/theta Vs theta')\n",
"b=-(4.5*10^-6)/400//gradient of graph is b \n",
"a=4.5*10^-6-(b*400)//finding the intercept on y axis by substututing the points(400,4.5) in line equation\n",
"printf('\n the value of b is %3.3e VdegC^-2',b)\n",
"printf('\n the value of a is %3.3e VdegC^-1',a)\n",
"\n",
" "
]
}
],
"metadata": {
"kernelspec": {
"display_name": "Scilab",
"language": "scilab",
"name": "scilab"
},
"language_info": {
"file_extension": ".sce",
"help_links": [
{
"text": "MetaKernel Magics",
"url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
}
],
"mimetype": "text/x-octave",
"name": "scilab",
"version": "0.7.1"
}
},
"nbformat": 4,
"nbformat_minor": 0
}
|
