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+{
+"cells": [
+ {
+		   "cell_type": "markdown",
+	   "metadata": {},
+	   "source": [
+       "# Chapter 12: Water transmission"
+	   ]
+	},
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 12.1: Example_1.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"//initialisation of variables\n",
+"c=100//in\n",
+"a=10//in\n",
+"Q=0.976//ft\n",
+"//CALCULATIONS\n",
+"G=a*Q//ft\n",
+"//RESULTS\n",
+"printf('the graphical basic =% f ft',G)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 12.2: Example_2.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"//initialisation of variables\n",
+"a=27.6//sq ft\n",
+"h=1.37//ft\n",
+"d=1.53*(27.9)^0.38*(1.36)^0.24//ft\n",
+"//CALCULATIONS\n",
+"R=d/4//ft\n",
+"A=(%pi*d^2)/4//sq ft\n",
+"//RESULTS\n",
+"printf('The diameter hydraulics radius and area of the hydraulically equivalent circular conduit=% f sq ft',A)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 12.3: Example_3.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"//initialisation of variables\n",
+"h1=13.5//ft\n",
+"h2=19.0//ft\n",
+"h3=27.5//ft\n",
+"c1=2.0*10^4//ft\n",
+"c2=2.1*10^4//ft\n",
+"c3=2.2*10^4//ft\n",
+"//CALCULATIONS\n",
+"H=h1+h2+h3//ft\n",
+"C=c1+c2+c3//ft\n",
+"//RESULTS\n",
+"printf('the most economical distributions of the available head=% f ft',C)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 12.4: Example_4.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"//initialisation of variables\n",
+"p=60//in\n",
+"h=20//percent\n",
+"a=1000//ft\n",
+"h1=40//percent\n",
+"c=0.5//ft\n",
+"p1=14.3//ft\n",
+"p2=6.1//ft\n",
+"d=11.7*10^-2//ft\n",
+"//CALCULATIONS\n",
+"P=p2/p1//ft\n",
+"D=d*p//ft\n",
+"//RESULTS\n",
+"printf('the air valve with a discharge the change in slop=% f ft',D)"
+   ]
+   }
+,
+{
+		   "cell_type": "markdown",
+		   "metadata": {},
+		   "source": [
+			"## Example 12.5: Example_5.sce"
+		   ]
+		  },
+  {
+"cell_type": "code",
+	   "execution_count": null,
+	   "metadata": {
+	    "collapsed": true
+	   },
+	   "outputs": [],
+"source": [
+"clc\n",
+"//initialisation of variables\n",
+"p=90//deg\n",
+"h=48//in\n",
+"p1=100//psig\n",
+"P=(1/2*%pi)*h^2*p1*0.7071//lb\n",
+"r=3000/54-31//ft\n",
+"s=9000//psi\n",
+"l=170//in\n",
+"b=6.5*10^-6//ft\n",
+"w=46//ft\n",
+"w1=1000//ft\n",
+"//CALCULATIONS\n",
+"D=(1/4*%pi)*h^2*p1//lb\n",
+"P=[r]*h^2//lb\n",
+"T=%pi*h*(1/4)*s//lb\n",
+"T1=(1/2)*l//tons\n",
+"Del=b*w*w1//ft per\n",
+"//RESULTS\n",
+"printf('the accorance with unless otherwise stated=% f ft per',Del)"
+   ]
+   }
+],
+"metadata": {
+		  "kernelspec": {
+		   "display_name": "Scilab",
+		   "language": "scilab",
+		   "name": "scilab"
+		  },
+		  "language_info": {
+		   "file_extension": ".sce",
+		   "help_links": [
+			{
+			 "text": "MetaKernel Magics",
+			 "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md"
+			}
+		   ],
+		   "mimetype": "text/x-octave",
+		   "name": "scilab",
+		   "version": "0.7.1"
+		  }
+		 },
+		 "nbformat": 4,
+		 "nbformat_minor": 0
+}