diff options
Diffstat (limited to 'Principles_Of_Geotechnical_Engineering_by_B_M_Das/7-permiability.ipynb')
-rw-r--r-- | Principles_Of_Geotechnical_Engineering_by_B_M_Das/7-permiability.ipynb | 355 |
1 files changed, 355 insertions, 0 deletions
diff --git a/Principles_Of_Geotechnical_Engineering_by_B_M_Das/7-permiability.ipynb b/Principles_Of_Geotechnical_Engineering_by_B_M_Das/7-permiability.ipynb new file mode 100644 index 0000000..b89d2d3 --- /dev/null +++ b/Principles_Of_Geotechnical_Engineering_by_B_M_Das/7-permiability.ipynb @@ -0,0 +1,355 @@ +{ +"cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 7: permiability" + ] + }, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.10: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"k1= 0.302e-7 //cm/sec\n", +"k2= 0.12e-7 //cm/sec\n", +"e1= 1.1\n", +"e2= 0.9\n", +"e= 0.75\n", +"//calcualtions\n", +"n= (log10((k1/k2)*((1+e1)/(1+e2))))/log10(e1/e2)\n", +"C= k1/(e1^n/(1+e1))\n", +"k= C*(e^n/(1+e))\n", +"//results\n", +"printf ('hydraulic conductivity = %e cm/sec ',k')" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.11: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"H1= 2 //m\n", +"H2= 3 //m\n", +"H3= 4 //m\n", +"k1= 1e-4 //cm/sec\n", +"k2= 3.2e-2 //cm/sec\n", +"k3= 4.1e-5 //cm/sec\n", +"//calculations\n", +"H= H1+H2+H3\n", +"Kh= (1/H)*((k1*H1)+(k2*H2)+(k3*H3))\n", +"Kv= H/((H1/k1)+(H2/k2)+(H3/k3))\n", +"P= Kh/Kv\n", +"//results\n", +"printf ('ration of equivalent hydraulic conductivity = % 2f ',P)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.12: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"H= 450 //mm\n", +"h= 150 //mm\n", +"k1= 1e-2 //cm/sec\n", +"k2= 3e-3 //cm/sec\n", +"k3= 4.9e-4 //cm/sec\n", +"h1= 300 //mm\n", +"//calculations\n", +"Kv= H/(h*(1/k1+1/k2+1/k3))\n", +"i= h1/H\n", +"q= Kv*i*100*3600\n", +"//results\n", +"printf ('rate of water supply = % 2f cm/hr ',q)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.1: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"L= 30 //cm\n", +"A= 177 //cm^2\n", +"h= 50 //cm\n", +"Q= 350 //cm^3\n", +"t= 300 //sec\n", +"//claculations\n", +"k=Q*L/(A*h*t)\n", +"//results\n", +"printf ('hydraulic conductivity = % 3f cm/sec ',k)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.2: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"L= 203 //mm\n", +"A= 10.3 //cm^2\n", +"a= 0.39 //cm^2\n", +"h0= 508 //mm\n", +"h180= 305 //mm\n", +"t= 180 //sec\n", +"//calculations\n", +"k= 2.303*a*L*log10(h0/h180)/(A*t)\n", +"//results\n", +"printf ('hydraulic conductivity of sand = % 2f in/sec ',k)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.3: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of varilables\n", +"k= 3e-7 //cm/sec\n", +"n= 0.0911e-4 //g*sec/cm^2\n", +"dw= 1 //g/cc\n", +"//calculations\n", +"K= k*n/dw\n", +"//results\n", +"printf ('absolute premeability = % 4f cm^2 ',K)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.4: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"k= 5.3e-5 //m/sec\n", +"H= 3 //m\n", +"a= 0.139 //radians\n", +"//calculations\n", +"A= H*cos(a)\n", +"i= sin(a)\n", +"q= k*i*A*3600\n", +"//results\n", +"printf ('rate of seepage = % 4f m^3/hr/m ',q)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.5: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"L= 50 //m\n", +"k= 0.08e-2//m/sec\n", +"h= 4 //m\n", +"H1= 3 //m\n", +"H= 8 //m\n", +"a= 0.139 //radians\n", +"//calculations\n", +"i= h*cos(a)/L\n", +"A= H1*cos(a)\n", +"q= k*i*A\n", +"//results\n", +"printf ('flow rate = % 2f m^3/sec/m ',q)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.6: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"k1= 0.02 //cm/sec\n", +"e1= 0.5 \n", +"e2= 0.65\n", +"//calculations\n", +"k2= k1*(e2^3/(1+e2))/(e1^3/(1+e1))\n", +"//results\n", +"printf ('hydraulic conductivity at void ratio of 0.65 = % 2f cm/sec ',k2)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.8: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"e= 0.6\n", +"D10= 0.09 //mm\n", +"//calculations\n", +"k= 2.4622*(D10^2*(e^3/(1+e)))^0.7825\n", +"//results\n", +"printf ('hydraulic conductivity = % 4f cm/sec ',k)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.9: solved.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"//initialisation of variables\n", +"e= 0.6\n", +"D10= 0.09 //mm\n", +"D60= 0.16 //mm\n", +"//calculations\n", +"Cu=D60/D10\n", +"k= 35*(e^3/(1+e))*(Cu^0.6)*(D10^2.32)\n", +"//results\n", +"printf ('hydraulic conductivity = % 3f cm/sec ',k)" + ] + } +], +"metadata": { + "kernelspec": { + "display_name": "Scilab", + "language": "scilab", + "name": "scilab" + }, + "language_info": { + "file_extension": ".sce", + "help_links": [ + { + "text": "MetaKernel Magics", + "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md" + } + ], + "mimetype": "text/x-octave", + "name": "scilab", + "version": "0.7.1" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |