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diff --git a/Fundamental_Of_Physics_by_D_Haliday/5-Force_and_Motion_l.ipynb b/Fundamental_Of_Physics_by_D_Haliday/5-Force_and_Motion_l.ipynb new file mode 100644 index 0000000..2683c61 --- /dev/null +++ b/Fundamental_Of_Physics_by_D_Haliday/5-Force_and_Motion_l.ipynb @@ -0,0 +1,351 @@ +{ +"cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 5: Force and Motion l" + ] + }, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.1: Sample_Problem_1.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci',-1)\n", +"\n", +"//Given that\n", +"m = .20 //in kg\n", +"F_1 = 4 * [1,0]\n", +"F_2 = 2 * [-1,0]\n", +"F_3 = 1 * [cos(dtor(30)),sin(dtor(30))]\n", +"\n", +"//Sample Problebb nmkn nm 5-1\n", +"printf('**Sample Problem 5-1**\n')\n", +"acceleration_a = F_1(1)/m\n", +"acceleration_b = F_2(1)/m\n", +"acceleration_c = (F_2(1) + F_3(1))/m\n", +"printf('The acceleration of puck in case a is %d m/s^2\n',acceleration_a)\n", +"printf('The acceleration of puck in case b is %d m/s^2\n',acceleration_b)\n", +"printf('The acceleration of puck in case c is %f m/s^2\n',acceleration_c)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.2: Sample_Problem_2.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci',-1)\n", +"\n", +"//Given that\n", +"mass = 2 //in kg\n", +"acceleration = 3 * [cos(dtor(50)),sin(dtor(50))] //in m/s^2\n", +"F1 = 10 * [cos(dtor(180+30)),sin(dtor(180+30))] //in N\n", +"F2 = 20 * [0,1] //in N\n", +"\n", +"//Sample Problem 5-2\n", +"printf('**Sample Problem 5-2**\n')\n", +"//from newton's first law\n", +"//F1 + F2 + F3 = mass * acceleration\n", +"F3 = mass * acceleration - F2 - F1\n", +"printf('The third Force vector F3 in N is')\n", +"disp(F3)\n", +"printf('The magnitude F3 is %f m/s\n', norm(F3))\n", +"printf('The angle made by F3 with the x axis in degrees %f', rtod(atan(F3(2)/F3(1))))" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.3: Sample_Problem_3.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci',-1)\n", +"\n", +"//GIven that\n", +"F_A = 220 * [cos(dtor(180-47)),sin(dtor(180-47))] //in N\n", +"F_B_dir = [0,-1]\n", +"F_C_mag = 170 //in N\n", +"\n", +"//Sample Problem 5-3\n", +"printf('**Sample Problem 5-3**\n')\n", +"//net sum of three forces must be zero\n", +"phi = acos(- F_A(1) / F_C_mag)\n", +"F_B_mag = F_C_mag * sin(phi) + F_A(2)\n", +"printf('The magnitude of Bettys force is %f N', F_B_mag)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.4: Sample_Problem_4.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci',-1)\n", +"\n", +"//Given that\n", +"g = 10 //in m/s^2\n", +"mass = 80 //in kg\n", +"theta = 30 //in degrees\n", +"Force_applied = 2.5 * mass * g * [cos(dtor(theta)),sin(dtor(theta))]\n", +"W_car = 7 * 10^5 //in N\n", +"distance = 1 //in meter\n", +"\n", +"//Sample Problem 5-4\n", +"printf('**Sample Problem 5-4**\n')\n", +"//using Newtons first law\n", +"acceleration = Force_applied(1) / (W_car /g)\n", +"//using newtons third equation of motion\n", +"v_final = sqrt(2 * acceleration * distance)\n", +"printf('The velocity after trevelling 1 m distance is %f m/s', v_final)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.5: Sample_Problem_5.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"g = 9.8 //in m/s^2\n", +"M = 3.3 //in kg\n", +"m = 2.1 //in kg\n", +"\n", +"//Sample Problem 5-5\n", +"printf('**Sample Problem 5-5**\n')\n", +"//from FBD1\n", +"//both will have common acceleration\n", +"//mg - T = ma\n", +"//T = Ma\n", +"//adding -> mg = (M+m)a\n", +"a = m * g /(M + m)\n", +"T = m *g - m *a\n", +"printf('The acceleration of both the blocks is %f m/s^2\n', a)\n", +"printf('The tension in the string is %f N', T)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.6: Sample_Problem_6.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci', -1)\n", +"\n", +"//Given that\n", +"g = 9.8 //in m/s^2\n", +"m = 15 //in kg\n", +"//from FBD\n", +"T = m *g\n", +"\n", +"//Sample Problem 5-6\n", +"printf('**Sample Problem 5-6**\n')\n", +"//we have-\n", +"//T1cos(28) - T2cos(47) = 0\n", +"//T1sin(28) + T2sin(47) = T\n", +"//therefore\n", +"mat_1 = [cos(dtor(28)),-cos(dtor(47));sin(dtor(28)),sin(dtor(47))]\n", +"mat_2 = [0 ; T]\n", +"//wr have -> mat_1 * ans = mat_2\n", +"mat_ans = inv(mat_1) * mat_2\n", +"printf('The tension in the first chord is %f N\n', mat_ans(1,1))\n", +"printf('The tension in the second chord is %f N\n', mat_ans(2,1))\n", +"printf('The tension in the third chord is %f N', T)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.7: Sample_Problem_7.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci', -1)\n", +"\n", +"//Given that\n", +"m = 15 //in kg\n", +"g = 9.8 //in m/s^2\n", +"T = m* g* sin(dtor(27))\n", +"N = m* g* cos(dtor(27))\n", +"\n", +"//Sample Problem 5-7a\n", +"printf('**Sample Problem 5-7a**\n')\n", +"printf('The tension in the chord is %f N\n', T)\n", +"printf('The Normal force is %f N\n', N)\n", +"\n", +"//Sample Problem 5-7b\n", +"printf('\n**Sample Problem 5-7b**\n')\n", +"a = g * sin(dtor(27))\n", +"printf('The acceleration of block after cutting the chord is %f m/s^2', a)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.8: Sample_Problem_8.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"g = 9.8 //in m/s^2\n", +"m = 72.2 //in kg\n", +"\n", +"//Sample Problem 5-8a\n", +"printf('**Sample Problem 5-8a**\n')\n", +"scale_read_b = m *g\n", +"printf('The reading of the scale in case a is %f ', scale_read_b)\n", +"\n", +"//Sample Problem 5-8b\n", +"printf('**Sample Problem 5-8b**\n')\n", +"//N - mg = ma\n", +"a_U = 3.2 //in m/s^2\n", +"scale_read_c_U = m * (g + a_U)\n", +"printf('The reading of the scale in case b if cab moves upaward is %f\n', scale_read_c_U)\n", +"a_D = -3.2 //in m/s^2\n", +"scale_read_c_D = m * (g + a_D)\n", +"printf('The reading of the scale in case b if cab moves downaward is %f\n', scale_read_c_D)\n", +"\n", +"//Sample Problem 5-8b\n", +"printf('\n**Sample Problem 5-8b**\n')\n", +"//using newtons second law => net force = mass * acceleration\n", +"F_net = m *a_U\n", +"printf('The net force on passenger during upward journey is %f N\n', F_net)\n", +"printf('The acceleration of passenger in the frame if cab is 0')" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 5.9: Sample_Problem_9.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Sample Problem 5-9a\n", +"F_ap = 20 //in N\n", +"m_A = 4 //in kg\n", +"m_B = 6 //in kg\n", +"\n", +"//Sample Problem 5-9a\n", +"printf('**Sample Problem 5-9a**\n')\n", +"ac = F_ap /(m_A + m_B)\n", +"printf('The comon acceleration of the blocks is %f m/s^2\n', ac)\n", +"\n", +"//Sample Problem 5-9b\n", +"printf('\n**Sample Problem 5-9b**\n')\n", +"//from FBD of A\n", +"//F - F_AB = m_A * a\n", +"F_AB = F_ap - m_A *ac\n", +"printf('The force on block B by Block A is %f N', F_AB)" + ] + } +], +"metadata": { + "kernelspec": { + "display_name": "Scilab", + "language": "scilab", + "name": "scilab" + }, + "language_info": { + "file_extension": ".sce", + "help_links": [ + { + "text": "MetaKernel Magics", + "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md" + } + ], + "mimetype": "text/x-octave", + "name": "scilab", + "version": "0.7.1" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |