diff options
Diffstat (limited to 'Concise_Physics_by_H_Matyaka/7-Electricity.ipynb')
-rw-r--r-- | Concise_Physics_by_H_Matyaka/7-Electricity.ipynb | 272 |
1 files changed, 272 insertions, 0 deletions
diff --git a/Concise_Physics_by_H_Matyaka/7-Electricity.ipynb b/Concise_Physics_by_H_Matyaka/7-Electricity.ipynb new file mode 100644 index 0000000..7542c66 --- /dev/null +++ b/Concise_Physics_by_H_Matyaka/7-Electricity.ipynb @@ -0,0 +1,272 @@ +{ +"cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 7: Electricity" + ] + }, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.1: Electric_potential_strength.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"e=1.6*10^-19 //charge of electron\n", +"r=0.075*10^-3 // radius of electron\n", +"ep=8.85*10^-12 //permittivity of free space\n", +"//calculation\n", +"v=-e/(4*%pi*ep*r)//electric potential\n", +"e=-e/(4*%pi*ep*r*r)//electric field strength\n", +"//output\n", +"printf('resultant potential is %3.3e V',v)\n", +"printf('\n resultant electric field strength %3.3f V/m',e)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.2: ratio_of_force.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"q=2.4*10^-19 //charge1\n", +"Q=3.8*10^-19//charge2\n", +"ep=8.85*10^-12//permittivity of free space\n", +"G=6.7*10^-11\n", +"m=8.9*10^-31//mass 1\n", +"M=1.5*10^-30//mass 2\n", +"//calculation\n", +"x=q*Q/(4*%pi*ep*m*M*G)//coulumbs law\n", +"//output\n", +"printf('the ratio of electrostatic force between charges %3.3e',x)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.3: emf_and_internal_resistance.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"i=0.5 //current in circuit\n", +"R=6 //resistance of circuit\n", +"i1=0.3//dropped current\n", +"//calculation\n", +"r=1.2/0.2\n", +"e=i*(r+R)//ohms law\n", +"//output\n", +"printf('the battery emf is %3.3f V',e)\n", +"printf('\n the internal resistence is %3.3f ohm',r)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.4: power_output.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"d=8.2*10^-7 //resistivity of coil\n", +"l=15 //length of wire\n", +"r=0.3*10^-3 //radius of wires\n", +"v=160 //power output\n", +"//calculations\n", +"R=d*l/(%pi*r*r)\n", +"p=v*v/R //for one coil\n", +"p1=v*v/(R+R) //for two coils in series\n", +"rp=(R*R)/(R+R)//total resistence \n", +"pp=(v*v)/rp//total power\n", +"//output\n", +"printf('the power when one coil is %3.3f W',p)\n", +"printf('\nthe power when two coils in series is %3.3f W',p1)\n", +"printf('\n the power when coils in parallel is %3.3f W',pp)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.5: percent_of_pd.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"r1=40//resistance 1\n", +"r2=20//resistamce 2\n", +"r3=10//resistance 3\n", +"v=1.6//voltage\n", +"//calculation\n", +"R=r1+r2+r3//total resistance in series\n", +"x=((v*r1)*70)/((2*50)*(1.6*40))//fraction of pd\n", +"x=x*100//percentage pd\n", +"//output\n", +"printf('the percentage of pd is %3.0f percent',x)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.6: final_resistance_calculation.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"a=4.3*10^-3//temperature co-efficient of resistance\n", +"//calculation\n", +"r2=((60*a+1)/(20*a+1))*10//resistance \n", +"//output\n", +"printf('the final resistence is %3.3f ohm',r2)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.7: internal_resistance_calculation.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"l1=82.3//balance length with switch open\n", +"l2=75.8//balance length with switch closed\n", +"R=9//resistance\n", +"//calculation\n", +"r=(R*l1/l2)-R//internal resistance\n", +"//output\n", +"printf('the internal resistence is %3.3f ohm',r)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 7.8: calculation_of_resistance.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"clc\n", +"clear\n", +"//input\n", +"p=2*10^-6//pd across wire\n", +"v=1.5//voltage \n", +"l=1.5*10^3//length of potentiometer\n", +"R=7//resistance\n", +"//calculation\n", +"vw=p*l//pd across the wire\n", +"x=(7*v/vw)-R//resistace of x\n", +"//output\n", +"printf('the resistance of x is %3.0f ohm',x)" + ] + } +], +"metadata": { + "kernelspec": { + "display_name": "Scilab", + "language": "scilab", + "name": "scilab" + }, + "language_info": { + "file_extension": ".sce", + "help_links": [ + { + "text": "MetaKernel Magics", + "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md" + } + ], + "mimetype": "text/x-octave", + "name": "scilab", + "version": "0.7.1" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |