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diff --git a/Chemical_Engineering_Thermodynamics_by_S_Sundaram/1-Introduction.ipynb b/Chemical_Engineering_Thermodynamics_by_S_Sundaram/1-Introduction.ipynb new file mode 100644 index 0000000..d326998 --- /dev/null +++ b/Chemical_Engineering_Thermodynamics_by_S_Sundaram/1-Introduction.ipynb @@ -0,0 +1,253 @@ +{ +"cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 1: Introduction" + ] + }, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 1.1: To_determine_the_force_exerted.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Chemical Engineering Thermodynamics\n", +"//Chapter 1\n", +"//Introduction\n", +"\n", +"//Example 1.1\n", +"clear;\n", +"clc;\n", +"\n", +"//Given \n", +"m = 100;//m is the mass of the object in kg\n", +"a = 10;//a is the acceeleration due to gravity in m/s^2\n", +"\n", +"//To determine the force exerted\n", +"F = m*a;//F is the force exerted by the object in kg\n", +"mprintf('Force exerted by the object= %f N',F);\n", +"F = (1/9.8065)*m*a;//F is the force exerted by the object in kgf\n", +"mprintf('\n Force exerted by the object= %f N',F);\n", +"//end" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 1.2: Theoretical_problem.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Chemical Engineering Thermodynamics\n", +"//Chapter\n", +"//Introduction\n", +"\n", +"//Example 1.2\n", +"clear;\n", +"clc;\n", +"\n", +"//Given\n", +"//The given example is a theoretical problem and it does not involve any numerical computation\n", +"//end" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 1.3: Theoretical_problem.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Chemical Engineering Thermodynamics\n", +"//Chapter\n", +"//Introduction\n", +"\n", +"//Example 1.3\n", +"clear;\n", +"clc;\n", +"\n", +"//Given\n", +"//The given example is a theoretical problem and it does not involve any numerical computation\n", +"//end" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 1.4: To_determine_the_mass_of_water_required.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Chemical Engineering Thermodynamics\n", +"//Chapter 1\n", +"//Introduction\n", +"\n", +"//Example 1.4\n", +"clear;\n", +"clc;\n", +"\n", +"//Given\n", +"h = 100;//h is the height of the water fall in m\n", +"n = .855;//n is the efficiency of the turbine\n", +"g = 9.8;//g is the acceleration due to gravity in m/(s^2)\n", +"E = 100*10*3600;//E is the potential enery of water available to the bulb for 10 hours in watt or J/s\n", +"\n", +"//To determine the mass of water required\n", +"m = (E/(g*h*n));//m is the mass of water required for lighting the bulb for 10 hours in Kg\n", +"mprintf('Mass of water required for lighting the bulb for 10 hours in Kg= %f Kg',m);\n", +"mprintf('\n Mass of water required for lighting the bulb for 10 hours in tonnes= %f Kg',m/907.2);\n", +"//end" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 1.5: To_Calculate_the_work_obtained.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Chemical Engineering Thermodynamics\n", +"//Chapter 1\n", +"//Introduction\n", +"\n", +"//Example 1.5\n", +"clear;\n", +"clc;\n", +"\n", +"//Given\n", +"n = 1;//n is the Kg mole of an ideal gas\n", +"P = 700*(10^4);//P is the pressure of the system in N/(m^2)\n", +"W = 45;//W is the weight of the mass in Kg\n", +"M = 20;//M is the weight of the piston and piston rod together in Kg\n", +"T = 300;//T is the constant temperature of the bath in K\n", +"h = .4;//h is the height difference of the piston after expansion in m\n", +"\n", +"//To calculate the work obtained\n", +"a = (10^-4);//a is the cross sectional area of the cylinder in m^2\n", +"V = h*a;//V is the volume changed as gas expands in m^3\n", +"\n", +"//(i). If gas alone is the system\n", +"//1Kgf = 9.8065Nm\n", +"P1 = ((W+M)*9.8065)/(10^-4);//P1 is the resisting pressure when the gas confined in the cylinder taken as a system\n", +"W1 = P1*V;//W1 is the work done if the gas confined in the cylinder us taken as system\n", +"mprintf('Work done by the system if the gas confined in the cylinder is taken as a system is %f Nm',W1);\n", +"\n", +"//(ii). If gas + piston + piston rod is a system\n", +"P2 = ((W*9.8065)/(10^-4));//P2 is the resisting pressure when the gas plus piston plus piston rod is taken as a system\n", +"W2 = P2*V;//W2 is the Work done by the system if the gas plus piston plus piston rod is taken as a system\n", +"mprintf('\n Work done by the system if the gas plus piston plus piston rod is taken as system is %f Nm',W2);\n", +"\n", +"//(iii). If gas + piston + piston rod +weight is system\n", +"P3 = 0;//P3 is the resisting pressure when the gas plus piston plus piston rod plus weight is taken as a system\n", +"W3 = P3*V;//W3 is the work done by the system if the gas plus piston plus piston rod plus weight is taken as a system\n", +"mprintf('\n Work done by the system if the gas plus piston plus piston rod plus weight is taken as a system is %f',W3);\n", +"//end" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 1.6: To_Calculate_the_work_done.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Chemical Engineering Thermodynamics\n", +"//Chapter 1\n", +"//Introduction\n", +"\n", +"//Example 1.6\n", +"clear;\n", +"clc;\n", +"\n", +"//Given\n", +"n = 1;//n is the Kg mole of ideal gas.\n", +"P1 = 700*(10^4);//P1 is the initial pressure of the system in N/(m^2)\n", +"P2 = 638*(10^4);//P2 is the final pressure of the system in N/(m^2)\n", +"T = 300;//T is temperature of the system in K\n", +"R = 8314.4;//R is gas constant in Nm/Kgmole deg K\n", +"\n", +"//To calculate the work done\n", +"W = n*R*T*log(P1/P2);//W is the work done by the system in Nm\n", +"mprintf('Work done by the system is %4.2e Nm',W);\n", +"//end" + ] + } +], +"metadata": { + "kernelspec": { + "display_name": "Scilab", + "language": "scilab", + "name": "scilab" + }, + "language_info": { + "file_extension": ".sce", + "help_links": [ + { + "text": "MetaKernel Magics", + "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md" + } + ], + "mimetype": "text/x-octave", + "name": "scilab", + "version": "0.7.1" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |