diff options
author | Prashant S | 2020-04-14 10:25:32 +0530 |
---|---|---|
committer | GitHub | 2020-04-14 10:25:32 +0530 |
commit | 06b09e7d29d252fb2f5a056eeb8bd1264ff6a333 (patch) | |
tree | 2b1df110e24ff0174830d7f825f43ff1c134d1af /Fundamental_Of_Physics_by_D_Haliday/29-Magnetic_fields.ipynb | |
parent | abb52650288b08a680335531742a7126ad0fb846 (diff) | |
parent | 476705d693c7122d34f9b049fa79b935405c9b49 (diff) | |
download | all-scilab-tbc-books-ipynb-master.tar.gz all-scilab-tbc-books-ipynb-master.tar.bz2 all-scilab-tbc-books-ipynb-master.zip |
Initial commit
Diffstat (limited to 'Fundamental_Of_Physics_by_D_Haliday/29-Magnetic_fields.ipynb')
-rw-r--r-- | Fundamental_Of_Physics_by_D_Haliday/29-Magnetic_fields.ipynb | 287 |
1 files changed, 287 insertions, 0 deletions
diff --git a/Fundamental_Of_Physics_by_D_Haliday/29-Magnetic_fields.ipynb b/Fundamental_Of_Physics_by_D_Haliday/29-Magnetic_fields.ipynb new file mode 100644 index 0000000..0fbfebe --- /dev/null +++ b/Fundamental_Of_Physics_by_D_Haliday/29-Magnetic_fields.ipynb @@ -0,0 +1,287 @@ +{ +"cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "# Chapter 29: Magnetic fields" + ] + }, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.1: Sample_Problem_1.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"B = 1.2*10^-3 //in T\n", +"e = 1.6*10^-19 //in C\n", +"K = 5.3*10^6*e //in J\n", +"m = 1.6*10^-27 //in kg\n", +"\n", +"//Sample Problem 29-1\n", +"printf('**Sample Problem 29-1**\n')\n", +"v = sqrt(2*K/m)\n", +"F = e*v*B\n", +"printf('The magnitude of magnetic force acting on the proton is %eN', F)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.2: Sample_Problem_2.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"d = 1.5*10^-2 //in meter\n", +"v = 4.0 //in m/s\n", +"B = 0.050 //in T\n", +"\n", +"//Sample Problem 29-2a\n", +"printf('**Sample Problem 29-2a**\n')\n", +"//force is in right direction\n", +"printf('The right surface will be at high potential\n')\n", +"\n", +"//Sample Problem 29-2b\n", +"printf('\n**Sample Problem 29-2b**\n')\n", +"F = v*B //force per unit charge\n", +"deltaU = d*F //energy per unit charge = potential difference\n", +"printf('The potential difference between the two surface is %1.1eV', deltaU)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.3: Sample_Problem_3.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"B = 80*10^-3 //in T\n", +"V = 1000.0 //in V\n", +"q = 1.6022*10^-19 //in C\n", +"x = 1.6254 //in m\n", +"conv = 1.6605*10^-27 //in kg/u\n", +"\n", +"//Sample Problem 29-3\n", +"printf('**Sample Problem 29-3**\n')\n", +"m = poly(0, 'm')\n", +"r = x/2\n", +"//r = m*v/(q*B)\n", +"//v = q*B*r/m\n", +"m = 0.5*(q*r*B)^2/V/q\n", +"printf('The mass of the particle is %ekg', m)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.4: Sample_Problem_4.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"exec('degree_rad.sci', -1)\n", +"\n", +"//Given that\n", +"e = 1.6*10^-19\n", +"K = 22.5*e //in J\n", +"B = 4.55*10^-4 //in T\n", +"theta = dtor(65.5)\n", +"m = 9.11*10^-31 //in kg\n", +"\n", +"//Sample Problem 29-4\n", +"printf('**Sample Problem 29-4**\n')\n", +"q = e\n", +"v = sqrt(2*K/m)\n", +"r = m*v*sin(theta)/(q*B)\n", +"T = 2*%pi*r/(v*sin(theta))\n", +"p = v*cos(theta)*T\n", +"printf('The pitch of the electron is equal to %fm', p)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.5: Sample_Problem_5.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"f = 12*10^6 //in Hz\n", +"R = 53*10^-2 //in m\n", +"q = 1.6*10^-19 //in C\n", +"m = 3.34*10^-27 //in kg\n", +"\n", +"//Sample Problem 29-5a\n", +"printf('**Sample Problem 29-5a**\n')\n", +"B = 2*%pi*m*f/q\n", +"printf('The magnitude of magnetic field should be %fT\n', B)\n", +"\n", +"//Sample Problem 29-5b\n", +"printf('\n**Sample Problem 29-5b**\n')\n", +"v = q*B*R/m\n", +"K = 0.5*m*v^2\n", +"printf('The kinetic energy of the deuteron will be %eJ', K)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.6: Sample_Problem_6.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"i = 28 //in A\n", +"LD = 46.6*10^-3 //in kg/m\n", +"g = 9.8 //in m/s^2\n", +"\n", +"//Sample Problem 29-6\n", +"printf('**Sample Problem 29-6**\n')\n", +"L = 1 //(say)\n", +"m = LD*L\n", +"B = m*g/i/L\n", +"printf('The minimum magnetic field required to suspend the wire is equal to %eT', B)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.7: Sample_Problem_7.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"h = 2.1*10^-2 //in m\n", +"w = 1.2*10^-2 //in m\n", +"n = 250\n", +"B = 0.23 //in T\n", +"i = 100*10^-6 //in A\n", +"theta = 28 //in degree\n", +"\n", +"//Sample Problem 29-7\n", +"printf('**Sample Problem 29-7**\n')\n", +"A = h*w\n", +"T = B*i*n*A\n", +"k = T/theta\n", +"printf('The value of constant k is equal to %eN.m/degree', k)" + ] + } +, +{ + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Example 29.8: Sample_Problem_8.sce" + ] + }, + { +"cell_type": "code", + "execution_count": null, + "metadata": { + "collapsed": true + }, + "outputs": [], +"source": [ +"//Given that\n", +"n = 250\n", +"A = 2.52*10^-4 //in m^2\n", +"i = 100*10^-6 //in A\n", +"B = 0.85 //in T\n", +"\n", +"//Sample Problem 29-8\n", +"printf('**Sample Problem 29-8**\n')\n", +"mu = n*i*A\n", +"U1 = -mu*B*cos(%pi/2)\n", +"U2 = -mu*B*cos(0)\n", +"W = U1 - U2\n", +"printf('Work done is equal to %eJ', W)" + ] + } +], +"metadata": { + "kernelspec": { + "display_name": "Scilab", + "language": "scilab", + "name": "scilab" + }, + "language_info": { + "file_extension": ".sce", + "help_links": [ + { + "text": "MetaKernel Magics", + "url": "https://github.com/calysto/metakernel/blob/master/metakernel/magics/README.md" + } + ], + "mimetype": "text/x-octave", + "name": "scilab", + "version": "0.7.1" + } + }, + "nbformat": 4, + "nbformat_minor": 0 +} |