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clc
disp("Example 3.8")
printf("\n")
printf("Given")
disp("Total current is 30mA")
disp("Branch currents are 20mA and 10mA")
disp("Equivalent resistance is equal to or greater than 10 ohm")
//From Fig 3.6
//Current flowing through R1 be i1 and let it be equal to 10mA
//Current flowing through R2 be i2 and let it be equal to 20mA
i1=10*10^-3;i2=20*10^-3;
i=30*10^-3;
//Let R1/(R1+R2)=X1 (1)
//Let R2/(R1+R2)=X2 (2)
X1=i1/i;
X2=i2/i;
//Let R1*R2(R1+R2)=Y (3)
//Given that
printf("\n Given")
disp("R1*R2(R1+R2)>=10")
//Solving (1),(2) and (3) we get
printf("R1>=%dohm\nR2>=%dohm\n",15,30)
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