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+//Chapter 3
+//Example 3.1
+//page 87
+//To calculate the capacitance to neutral of a single phase line
+clear;clc;
+r=0.328; //radius of the conductors
+D=300; //distance between the conductors
+h=750; //height of the conductors
+
+//calculating capacitance neglecting the presence of ground
+//using Eq (3.6)
+Cn=(0.0242/(log10(D/r)));
+printf("\nCapacitance to neutral /km of the given single phase line neglecting presence of the earth (using Eq 3.6) is = %0.5f uF/km\n\n",Cn);
+
+//using Eq (3.7)
+Cn=(0.0242)/log10((D/(2*r))+((D^2)/(4*r^2)-1)^0.5);
+printf("Capacitance to neutral /km of the given single phase line neglecting presence of the earth (using Eq 3.7) is = %0.5f uF/km\n\n",Cn);
+
+//Consudering the effect of earth and neglecting the non uniformity of the charge
+Cn=(0.0242)/log10(D/(r*(1+((D^2)/(4*h^2)))^0.5));
+printf("Capacitance to neutral /km of the given single phase line considering the presence of the earth and neglecting non uniformity of charge distribution (using Eq 3.26b) is = %0.5f uF/km\n\n",Cn);
+