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Diffstat (limited to 'Working_Examples/83/CH2/EX2.5')
-rwxr-xr-x | Working_Examples/83/CH2/EX2.5/example_2_5.sce | 34 | ||||
-rwxr-xr-x | Working_Examples/83/CH2/EX2.5/result_example_2_5.txt | 15 |
2 files changed, 49 insertions, 0 deletions
diff --git a/Working_Examples/83/CH2/EX2.5/example_2_5.sce b/Working_Examples/83/CH2/EX2.5/example_2_5.sce new file mode 100755 index 0000000..dc380bd --- /dev/null +++ b/Working_Examples/83/CH2/EX2.5/example_2_5.sce @@ -0,0 +1,34 @@ +//Chapter 2 +//Example 2.5 +//page 63 +//To find flux linkages with neutral and voltage induced in neutral +//To find voltage drop in each of three-phase wires + +clear;clc; +Ia=-30+%i*50; +Ib=-25+%i*55; +Ic=-(Ia+Ib); + +//(a) to find flux linkages with neutral and voltage induce in it +Dan=4.5; +Dbn=3; //from figure +Dcn=1.5; +Phi_n=2*10^(-7)*(Ia*log(1/Dan)+Ib*log(1/Dbn)+Ic*log(1/Dcn)); +Vn=%i*2*%pi*50*Phi_n*15000; //voltage induced for 15km long TL +Vn=abs(Vn) ; +printf("\nFlux linkages of the neutral wire = %f Wb-T/m\n\n",Phi_n); +printf("Voltage induced in the neutral = %d\n\n",Vn); + +//(b) to find voltage drop in each phase +Phi_a=2*10^(-7)*(Ia*log(1/(0.7788*0.005))+Ib*log(1/1.5)+Ic*log(1/3)); +Phi_b=2*10^(-7)*(Ib*log(1/(0.7788*0.005))+Ia*log(1/1.5)+Ic*log(1/1.5)); +Phi_c=2*10^(-7)*(Ic*log(1/(0.7788*0.005))+Ib*log(1/1.5)+Ia*log(1/3)); + +delta_Va=%i*2*%pi*50*Phi_a*15000; //like we did for neutral voltage +delta_Vb=%i*2*%pi*50*Phi_b*15000; +delta_Vc=%i*2*%pi*50*Phi_c*15000; + +printf("The Voltage drop of phase a(in volts) =");disp(delta_Va); +printf("\n\nThe Voltage drop of phase b(in volts) =");disp(delta_Vb); +printf("\n\nThe Voltage drop of phase c(in volts) =");disp(delta_Vc); + diff --git a/Working_Examples/83/CH2/EX2.5/result_example_2_5.txt b/Working_Examples/83/CH2/EX2.5/result_example_2_5.txt new file mode 100755 index 0000000..1b29086 --- /dev/null +++ b/Working_Examples/83/CH2/EX2.5/result_example_2_5.txt @@ -0,0 +1,15 @@ + +Flux linkages of the neutral wire = 0.000010 Wb-T/m + +Voltage induced in the neutral = 99 + +The Voltage drop of phase a(in volts) = + - 349.1594 - 204.26943i + + +The Voltage drop of phase b(in volts) = + - 308.62198 - 140.28272i + + +The Voltage drop of phase c(in volts) = + 621.85121 + 328.22026i |