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+//Chapter 11
+//Example 11.5
+//page 413
+//To find Double line to ground fault current and voltage of healthy phase
+clc;clear;
+
+Z1eq=0.09*%i;
+Z2eq=0.075*%i;
+Z0=(%i*0.1);
+Ea=1;
+a=(-0.5+%i*sqrt(3)/2);
+
+//to find the sequence components of healthy phase
+Ia1=Ea/(Z1eq+(Z2eq*Z0/(Z2eq+Z0)));
+Va1=Ea-(Ia1*Z1eq);
+Va2=Va1;
+Va0=Va1;
+
+Ia2=-(Va2/Z2eq);
+Ia0=-(Va0/Z0);
+
+I=[1 1 1;a^2 a 1;a a^2 1]*[Ia1; Ia2; Ia0];
+
+//voltage of the healthy phase
+Va=3*Va1;
+
+//displaying the results
+printf('Ia1=-j%0.3f\n',abs(Ia1));
+printf(' Ia2=j%0.3f\n',abs(Ia2));
+printf(' Ia0=j%0.3f\n\n',abs(Ia0));
+
+printf(' Ia=%0.3f + j%0.3f\n',real(I(1,1)),imag(I(1,1)));
+printf(' Ib=%0.3f + j%0.3f\n',real(I(2,1)),imag(I(2,1)));
+printf(' Ic=%0.3f + j%0.3f\n\n',real(I(3,1)),imag(I(3,1)));
+
+printf(' Voltage of the healthy phase Va=3Va1=%0.3f',Va); \ No newline at end of file