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diff --git a/Working_Examples/2777/CH6/EX6.25/Ex6_25.sce b/Working_Examples/2777/CH6/EX6.25/Ex6_25.sce new file mode 100755 index 0000000..1259182 --- /dev/null +++ b/Working_Examples/2777/CH6/EX6.25/Ex6_25.sce @@ -0,0 +1,46 @@ +
+// ELECTRICAL MACHINES
+// R.K.Srivastava
+// First Impression 2011
+// CENGAGE LEARNING INDIA PVT. LTD
+
+// CHAPTER : 6 : SYNCHRONOUS MACHINES
+
+// EXAMPLE : 6.25
+
+clear ; clc ; close ; // Clear the work space and console
+
+
+// GIVEN DATA
+
+v = 440; // Operating voltage of the Synchronous generator in Volts
+f = 50; // Operating Frequency of the Synchronous generator in Hertz
+m = 3; // Total number of Phase
+pf = 0.8; // Power factor lagging
+Il = 100; // Motor drawing current in Amphere
+xs = 2; // Synchronous reactances in Ohms
+delta = 20; // Power angle in degree
+P = 50*10^3; // Total Power developed by the motor in Watts
+Ppp = (50*10^3)/3; // Power developed by the motor per phase in Watts
+
+
+// CALCULATIONS
+
+V = v/sqrt(3); // Phase voltage in Volts
+Eo = (Ppp*xs)/(3*V*sind(delta)); // Per phase Induced voltage in Volts
+// Let us assume thetam is Power factor angle in degree and Im is the Motor current now, from phasor diagram figure 6.67 page no. 465 we get, Eo*cosd(delta) = V+Im*xs*sind(thetam), Im*sind(thetam) = ((383.84*cosd(20))-254.03)/2 = 53.35 and Im*xs*cosd(thetam) = Eo*sin(delta), Im*cosd(theta) = ((383.84*sind(20))/2 = 65.60 by sloving these two equations we get Im = sqrt(65.60^2 + 53.35^2) = 84.56 A and thetam = atand(53.35/65.60) = 39.13 degree
+Im = sqrt(65.60^2 + 53.35^2); // Motor current in Amphere
+thetam = atand(53.35/65.60); // Power factor angle in degree
+kVA = (sqrt(3)*V*Im*sind(thetam))/1000; // Rective kVA of the motor in kVAR
+thetal = acosd(pf); // Load power factor angle in degree
+thetaR = atand((Im*sind(thetam)-Il*sind(thetal))/(Im*cosd(thetam)+Il*cosd(thetal))); // Resultant Power factor angle in degree
+ovpf = cosd(thetaR); // Overall Power factor lagging
+IR = sqrt((Im*sind(thetam)-Il*sind(thetal))^2 + (Im*cosd(thetam)+Il*cosd(thetal))^2); // Resultant (magnitude) current in Amphere refer phasor diagram figure 6.69 page no. 467
+
+
+// DISPLAY RESULTS
+
+disp("EXAMPLE : 6.25: SOLUTION :-");
+printf("\n (a) Rective kVA of the motor = %.3f kVAR \n",kVA)
+printf("\n (b) Overall Power factor of the load and motor = %.4f lagging and \n",ovpf)
+printf("\n Resultant (magnitude) current = %.2f A \n",IR)
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