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+
+// ELECTRICAL MACHINES
+// R.K.Srivastava
+// First Impression 2011
+// CENGAGE LEARNING INDIA PVT. LTD 
+
+// CHAPTER : 3 : TRANSFORMERS 
+
+// EXAMPLE : 3.6
+
+clear ; clc ; close ; // Clear the work space and console
+
+
+// GIVEN DATA
+
+S = 5;                  // Transformer Rating in kVA
+V1 = 220;               // HV side voltage in volts
+V2 = 110;               // LV side voltage in Volts
+P = 4 * 10 ^ 2;         // Load of the Transformer
+pf = 0.8;               // Power Factor (lagging)
+f = 50;                 // Frequency in Hertz
+
+
+// CALCULATIONS
+
+a = V1/V2;              // Turn Ratio of the Transformer
+
+// case (a) At full load
+I1 = (S * 10 ^ 3)/V1;       // Primary current at full load in Amphere
+I2 = (S * 10 ^ 3)/V2;       // Secondary Current at full Load in Amphere
+
+// Case (b) At 4kW, 0.8 lagging pf load
+I11 = (4 * 10 ^ 3 * 0.8)/V1;       // Primary current At 4kW, 0.8 lagging pf load in Amphere
+I22 = (4 * 10 ^ 3 * 0.8)/V2;       // Secondary Current At 4kW, 0.8 lagging pf load in Amphere
+
+
+// DISPLAY RESULTS
+
+disp("EXAMPLE : 3.6 : SOLUTION :-") ;
+printf("\n   (a)   Turn Ratio of the Transformer , a = %.f \n ",a);
+printf("\n (b.1.1) Primary current at full load , I1 = %.2f A \n",I1);
+printf("\n (b.1.2) Secondary current at full load , I2 = %.2f A \n ",I2);
+printf("\n (b.2.1) Primary current at 4kW, 0.8 lagging pf load , I1 = %.3f A \n",I11);
+printf("\n (b.2.1) Secondary current at 4kW, 0.8 lagging pf load , I2 = %.3f A \n",I22);