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+clc
+disp("Example 14.8")
+printf("\n")
+
+//From figure 14.10
+//By inspection
+//V1=10^9*I1
+//V2=10(I2-10^-3*V1)
+
+
+//On solving we get
+disp("I1=10^-9*V1 (1)");
+disp("V2=10*I2-10^-2*V1 (2)");
+
+
+//The equations which contain g parameters are
+//I1=g11*V1+g12*I2
+//V2=g21*V1+g22*I2
+
+//On comparing (1) and (2) with above equations
+
+printf("\ng11=%2.1e\n",10^-9);
+printf("g12=%d\n",0);
+printf("g21=%2.1e\n",-10^-2);
+printf("g22=%d\n",10);