diff options
Diffstat (limited to 'Working_Examples/154/CH13')
-rwxr-xr-x | Working_Examples/154/CH13/EX13.2/ch13_2.sce | 31 | ||||
-rwxr-xr-x | Working_Examples/154/CH13/EX13.7/ch13_7.sce | 21 | ||||
-rwxr-xr-x | Working_Examples/154/CH13/EX13.8/ch13_8.sce | 21 |
3 files changed, 73 insertions, 0 deletions
diff --git a/Working_Examples/154/CH13/EX13.2/ch13_2.sce b/Working_Examples/154/CH13/EX13.2/ch13_2.sce new file mode 100755 index 0000000..b4b8409 --- /dev/null +++ b/Working_Examples/154/CH13/EX13.2/ch13_2.sce @@ -0,0 +1,31 @@ +clc
+disp("Problem 13.2")
+printf("\n")
+
+printf("Given")
+disp("|Hv|=1/sqrt(2) (1)")
+disp("Resistance R1=5kohm")
+R1=5000;
+disp("Hv(w)=1/1+%i*(w/wx) (2)")
+//wx=1/(R1*C2)
+//On solving we get
+disp("wx=2*10^-4/C2 (3)")
+
+disp("a)")
+C2=10*10^-9;
+//Taking modulus of (2)
+disp("|Hv(w)|=1/sqrt(1+(w/wx)^2)")
+//Equating (1) and (2)
+wx=2*10^-4/C2;
+fx=(wx/(2*%pi))*10^-3
+printf("Frequency(a) is %3.2fkHz\n",fx)
+
+disp("b)")
+C2b=1*10^-9;
+//As frequency is inversely proportional to C2 (from (3))
+fx1=(C2/C2b)*fx
+printf("Frequency(b) is %3.2fkHz\n",fx1)
+
+
+
+
diff --git a/Working_Examples/154/CH13/EX13.7/ch13_7.sce b/Working_Examples/154/CH13/EX13.7/ch13_7.sce new file mode 100755 index 0000000..34dda83 --- /dev/null +++ b/Working_Examples/154/CH13/EX13.7/ch13_7.sce @@ -0,0 +1,21 @@ +clc
+disp("Problem 13.7")
+printf("\n")
+
+s=%s;
+printf("Given")
+H=(10*s)/(s^2+300*s+10^6)
+disp(H,"H(s)=")
+//From the above transfer function
+//Comparing the denominator with s^2+a*s+b with w=sqrt(b)
+a=300;b=10^6;
+//Therefore center frequency is
+w0=sqrt(10^6)
+//The lower and upper frequencies are
+wl=sqrt(a^2/4+b)-a/2
+wh=sqrt(a^2/4+b)+a/2
+B=wh-wl //It can be inferred that B=a
+Q=sqrt(b)/a
+printf("\nCenter frequency= %drad/s\n",w0);
+printf("Low power frequency = %3.2frad/s\nHigh power frequency = %3.2frad/s\n",wl,wh);
+printf("Bandwidth= %drad/s\nQuality factor =%3.2f\n",B,Q)
diff --git a/Working_Examples/154/CH13/EX13.8/ch13_8.sce b/Working_Examples/154/CH13/EX13.8/ch13_8.sce new file mode 100755 index 0000000..a2b2331 --- /dev/null +++ b/Working_Examples/154/CH13/EX13.8/ch13_8.sce @@ -0,0 +1,21 @@ +clc
+disp("Problem 13.8")
+printf("\n")
+
+s=%s;
+printf("Given")
+H=(10*s)/(s^2+30*s+10^6)
+disp(H,"H(s)=")
+//From the above transfer function
+//Comparing the denominator with s^2+a*s+b with w=sqrt(b)
+a=30;b=10^6;
+//Therefore center frequency is
+w0=sqrt(10^6)
+//The lower and upper frequencies are
+wl=sqrt(a^2/4+b)-a/2
+wh=sqrt(a^2/4+b)+a/2
+B=wh-wl
+Q=sqrt(b)/a
+printf("\nCenter frequency= %drad/s\n",w0);
+printf("Low power frequency = %3.2frad/s\nHigh power frequency = %3.2frad/s\n",wl,wh);
+printf("Bandwidth= %drad/s\nQuality factor =%3.2f\n",B,Q)
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