Xcos examples from textbooks and for blocksHEADmaster

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diff --git a/Working_Examples/83/CH5/EX5.11/example_5_11.sce b/Working_Examples/83/CH5/EX5.11/example_5_11.sce
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+//Chapter 5
+//Example 5.11
+//page 172
+//To determine sending-end voltage.maximum power delivered
+clear;clc;
+
+A=0.93*(cosd(1.5)+%i*sind(1.5));
+B=115*(cosd(77)+%i*sind(77));
+Vr=275;
+Ce=abs(A/B)*Vr^2;
+printf('Centre of the receiving end circle is = %0.1f MVA\n\n',Ce);
+CrP=850;Vs=CrP*abs(B)/Vr;
+printf('(a) From the diagram,\n\tCrP=%d \n \tSending end voltage|Vs|= %0.1f kV\n\n',CrP,Vs);
+Vs=295; //given
+r=(Vs*Vr)/abs(B);
+Pr_m=556; //from the diagram
+printf('(b) Radius of the circle diagram = %0.1f MVA\n\t PR_max=%d MW\n\n',r,Pr_m);
+Ps=295; //from the diagram;
+printf('(c) Additional MVA to be drawn from the line is = P''S=%d MVAR\n\n',Ps);
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diff --git a/Working_Examples/83/CH5/EX5.11/result_example_5_11.txt b/Working_Examples/83/CH5/EX5.11/result_example_5_11.txt
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+ 
+
+Centre of the receiving end circle is = 611.6 MVA
+
+(a) From the diagram,
+	CrP=850 
+ 	Sending end voltage|Vs|= 355.5 kV
+
+(b) Radius of the circle diagram = 705.4 MVA
+	 PR_max=556 MW
+
+(c) Additional MVA to be drawn from the line is = P'S=295 MVAR