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authorSiddharth Agarwal2019-09-03 18:27:40 +0530
committerSiddharth Agarwal2019-09-03 18:27:40 +0530
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+// ELECTRICAL MACHINES
+// R.K.Srivastava
+// First Impression 2011
+// CENGAGE LEARNING INDIA PVT. LTD
+
+// CHAPTER : 7 : SPECIAL MOTORS AND INTRODUCTION TO GENERALIZED MACHINE THEORY
+
+// EXAMPLE : 7.8
+
+clear ; clc ; close ; // Clear the work space and console
+
+
+// GIVEN DATA
+
+V = 220; // supply voltage in Volts
+f = 50; // Frequency in Hertz
+p = 4; // Number of poles
+Xm = 60; // Mutual reactance in Ohms
+Rs = 1.0; // Resistance of stator windings in Ohms
+Xs = 6.0; // Leakage reactance of stator windings in Ohms
+Ra = 2.5; // Resistance of Armature windings in Ohms
+Xa = 6.0; // Leakage reactance of armature windings in Ohms
+P_hp = 1; // Output power in HP
+N = 1400; // Motor running speed in RPM
+alpha = 15; // Brush displacement from the low-impedance position in degree
+
+// CALCULATIONS
+
+Ns = (120*f)/p; // Synchronous speed in RPM
+s = N/Ns; // Speed ratio
+I = V / (Rs + %i*(Xs+Xm) + (%i*Xm^2*cosd(alpha))*(s*sind(alpha)-(%i*cosd(alpha)))/(Ra+%i*(Xa+Xm))); // Curent in Amphere
+pf = cosd(atand(imag(I),real(I))); // Power factor lagging
+
+
+// DISPLAY RESULTS
+
+disp("EXAMPLE : 7.8: SOLUTION :-");
+printf("\n (a) Currents, I = %.2f < %.2f A \n",abs(I),atand(imag(I),real(I)))
+printf("\n (b) Power factor = %.4f lagging \n",pf)