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| author | Siddharth Agarwal | 2019-09-03 18:27:40 +0530 |
|---|---|---|
| committer | Siddharth Agarwal | 2019-09-03 18:27:40 +0530 |
| commit | 8ac15bc5efafa2afc053c293152605b0e6ae60ff (patch) | |
| tree | e1bc17aae137922b1ee990f17aae4a6cb15b7d87 /Working_Examples/2777/CH3/EX3.19 | |
| parent | 52a477ec613900885e29c4a0b02806a415b4f83a (diff) | |
| download | Xcos_block_examples-master.tar.gz Xcos_block_examples-master.tar.bz2 Xcos_block_examples-master.zip | |
Diffstat (limited to 'Working_Examples/2777/CH3/EX3.19')
| -rwxr-xr-x | Working_Examples/2777/CH3/EX3.19/Ex3_19.sce | 38 |
1 files changed, 38 insertions, 0 deletions
diff --git a/Working_Examples/2777/CH3/EX3.19/Ex3_19.sce b/Working_Examples/2777/CH3/EX3.19/Ex3_19.sce new file mode 100755 index 0000000..f64cc2f --- /dev/null +++ b/Working_Examples/2777/CH3/EX3.19/Ex3_19.sce @@ -0,0 +1,38 @@ +
+// ELECTRICAL MACHINES
+// R.K.Srivastava
+// First Impression 2011
+// CENGAGE LEARNING INDIA PVT. LTD
+
+// CHAPTER : 3 : TRANSFORMERS
+
+// EXAMPLE : 3.19
+
+clear ; clc ; close ; // Clear the work space and console
+
+
+// GIVEN DATA
+
+Sa = 200; // Rating of the TWO 1-Phase Transformer in kVA
+Z1 = 0.005 + 0.08 * %i // Equivalent Impedance of the Transformer-1 in Per-Unit
+Z2 = 0.0075 + 0.04 * %i // Equivalent Impedance of the Transformer-2 in Per-Unit
+P = 400; // Total load in kiloWatts
+Cos_theta = 1.0; // Unity power factor
+
+
+// CALCULATIONS
+
+kVA = P/Cos_theta; // kVA rating of the Transformer
+S = kVA; // kVA rating of the Transformer
+S1 = ( Z2/(Z1+Z2) )*S; // Load shared by Transformer-1 in kVA
+S2 = S - S1; // Load shared by Transformer-2 in kVA
+
+
+// DISPLAY RESULTS
+
+disp("EXAMPLE : 3.19 : SOLUTION :-") ;
+printf("\n (a) Load shared by Transformer-1 , S1 = %.2f+j(%.2f) kVA \n ",real(S1),imag(S1));
+printf("\n (b )Load shared by Transformer-2 , S2 = %.2f+j%.2f kVA \n ",real(S2),imag(S2));
+printf("\n\n [ TEXT BOOK SOLUTION IS PRINTED WRONGLY ( I verified by manual calculation )]\n" );
+printf("\n WRONGLY PRINTED ANSWERS ARE :- (a) S1 = (-131.90)+j(38.47)kVA instead of %.2f+j(%.2f) kVA \n ",real(S1),imag(S1));
+printf("\n (b) S2 = (268.1)+j(.38047)kVA instead of %.2f+j%.2f kVA \n ",real(S2),imag(S2));
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