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author | Ankit Raj | 2017-06-21 11:00:07 +0530 |
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committer | Ankit Raj | 2017-06-21 11:00:07 +0530 |
commit | 6e4535ef3a2c3ec3a4c857673a43938fd04cba80 (patch) | |
tree | fe54b879807b9983de491c73b3708c07129c51db /2.3-1/src/c/elementaryFunctions/discrete_mathematics/gcd | |
parent | 02a004ea1500c403ac1a18a52aaf79aaeb7280ed (diff) | |
download | Scilab2C-6e4535ef3a2c3ec3a4c857673a43938fd04cba80.tar.gz Scilab2C-6e4535ef3a2c3ec3a4c857673a43938fd04cba80.tar.bz2 Scilab2C-6e4535ef3a2c3ec3a4c857673a43938fd04cba80.zip |
Functions added - string related and signal processing
Diffstat (limited to '2.3-1/src/c/elementaryFunctions/discrete_mathematics/gcd')
-rw-r--r-- | 2.3-1/src/c/elementaryFunctions/discrete_mathematics/gcd/u8gcda.c | 60 |
1 files changed, 60 insertions, 0 deletions
diff --git a/2.3-1/src/c/elementaryFunctions/discrete_mathematics/gcd/u8gcda.c b/2.3-1/src/c/elementaryFunctions/discrete_mathematics/gcd/u8gcda.c new file mode 100644 index 00000000..3d586232 --- /dev/null +++ b/2.3-1/src/c/elementaryFunctions/discrete_mathematics/gcd/u8gcda.c @@ -0,0 +1,60 @@ +/* Copyright (C) 2017 - IIT Bombay - FOSSEE + + This file must be used under the terms of the CeCILL. + This source file is licensed as described in the file COPYING, which + you should have received as part of this distribution. The terms + are also available at + http://www.cecill.info/licences/Licence_CeCILL_V2-en.txt + Author: Ankit Raj + Organization: FOSSEE, IIT Bombay + Email: toolbox@scilab.in +*/ +#include<stdio.h> +/* This is the "gcd" function , which takes two input. first + one is the array and the second one is the length of the array. + Now to calculate the gcd of two elements we fin the maximum of + the two elements, and then iterate from maximum value down to 1, + and check whether the particular value divides the two elements. + And in this way we can calculate the gcd of the whole array. +*/ +#include "gcd.h" +uint8 u8gcdua(uint8* in,int size) +{ + + int temp; + if(size==1) + { + temp=*in; + } + else + { + int x=*in; + int y=*(in+1); + int max=(x>y)?x:y; + for(int i=max;i>=1;i--) + { + if(x%i==0 && y%i==0) + { + temp=i; + break; + } + } + for(int j=2;j<size;j++) + { + x=temp; + y=*(in+j); + max=(x>y)?x:y; + for(int i=max;i>=1;i--) + { + if(x%i==0 && y%i==0) + { + temp=i; + break; + } + } + } +} + + return temp; +} + |