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//Example 6.3.
clc
format(6)
alpha=0.967
IE=10
disp("The common-base d.c. current gain (alpha) is,")
disp("alpha = 0.967 = IC/IE = IC/10")
IC=alpha*IE
disp(IC,"Therefore, IC(mA) = ")
disp("The emitter current, IE = IB + IC")
IB=IE-IC
disp(IB,"Therefore, IB(mA) = ")
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