991/CH6/EX6.1/Example6_1.sce


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//Example 6.1.
clc
format(5)
IE=10
IC=9.8
disp("The emitter current is,")
disp("IE = IB + IC")
disp("10 = IB + 9.8")
IB=IE-IC
disp(IB,"Therefore,    IB(mA) = ")