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//Example 18.2.
clc
format(6)
icd=(24/500)*10^3 // in mA
disp(icd,"Average value of load current, Id.c.(mA) = Vdc / RL =")
im=%pi*48 // in mA
disp(im,"Maximum value of load current, Im(mA) = pi * Idc =")
disp("Therefore, maximum ac voltage required at the input,")
vm=550*150.8*10^-3 // in V
disp(vm," Vm(V) = Im * (rf+RL) =")
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