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//Example 14.2.
clc
format(6)
Af=100
dAf=0.02
dA=0.2
disp("We have, dAf/Af = dA/A * 1/(1+A*beta)")
disp(" dAf/Af = dA/A * 1/(1+A*beta)")
Ab=dA/dAf
disp(Ab,"Therefore, (1 + A*beta) =")
disp("Also, the gain with feedback is")
disp(" Af = A / (1+A*beta)")
A=Af*Ab
disp(A,"Therefore, A =")
disp(" 1 + A*beta = 10; i.e. A*beta = 9")
beta=9/A
disp(beta,"Therefore, beta =")
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