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//Chapter 2
//Example 2_5
//PAge 18
clear;clc;
power=100;
cv=6400;
n_thermal =0.3;
n_electrical =0.92;
//coal consumption
n_overall = n_thermal*n_electrical;
ugpa=power*1000;
h=ugpa*860/n_overall;
printf("Coal consumption per hour = %.1f kg \n\n", h/cv);
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