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//chapter-2,Example2_8,pg 485
R1=10*10^3
R2=10*10^3
V1=10//input voltage-1
V2=10//input voltage-2
R31=10*10^3//R3,case-1
Vo1=((1+(R2/R1)+(R2/R31))*V1)-(R2/R1)*V2//output voltage case-1
printf("output voltage case-1\n")
printf("Vo1=%.2f V\n",Vo1)
R32=100*10^3//R3,case-2
Vo2=((1+(R2/R1)+(R2/R32))*V1)-(R2/R1)*V2//output voltage case-2
printf("output voltage case-2\n")
printf("Vo2=%.2f V\n",Vo2)
R33=1000*10^3//R3,case-3
Vo3=((1+(R2/R1)+(R2/R33))*V1)-(R2/R1)*V2//output voltage case-3
printf("output voltage case-3\n")
printf("Vo3=%.2f V",Vo3)
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