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//chapter2,Example2_2,pg 22
V1=5//input-1
V2=5//input-2
V12=50*10^-3//difference input
Vo=2//output voltage
acc=0.01//accuracy
Ad=(Vo/V12)//diffrential gain
//error at the output should be less than (2/100)V or 20mV.if common mode gain is the only source of error then
err=Vo*acc//error
Acm=(err/V1)//common mode gain
CMRR=20*log10(Ad/Acm)//common mode rejection ratio in dB
printf("diffrential gain \n")
printf("\nAd=%.1f \n",Ad)
printf("common mode gain \n")
printf("\nAcm=%.4f \n",Acm)
printf("\nCMRR=%.1f dB\n",CMRR)
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