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//Example 8.6
clear;
clc;
a0=3600;
f1=1*10^6;
f2=4*10^6;
f3=40*10^6;
fmin135=4.78*10^6;
fmin180=14.3*10^6;
gbp1=abs(a0/[(1+(%i*(fmin135/f1)))*(1+(%i*(fmin135/f3)))*(1+(%i*(fmin135/f3)))])-256;
gbp2=abs(a0/[(1+(%i*(fmin180/f1)))*(1+(%i*(fmin180/f3)))*(1+(%i*(fmin180/f3)))])-158.97561;
printf("|a(j*fmin135)|=%.d V/V",gbp1);
printf("\n|a(j*fmin180)|=%.1f V/V",gbp2);
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