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//Example 6.9
clear;
clc;
f0=10*10^3;
Q=25;
HobpdB=0;
R1=10*10^3;//Assumption
R2=R1;//Assumption
R5=R1;//Assumption
R6=R1;//Assumption
R3=250*10^3;//Assumption
R4=R3;//Assumption
C1=1/(2*%pi*f0*R5);//Assumption
C2=C1;//Assumption
f0reler=0.01;//as relative error defined for f0=1%
Qreler=0.01
ftf0=f0/f0reler;
ftQ=(4*Q*f0)/Qreler;
printf("Designed Biquad Filter :")
printf("\nR1=R2=R5=R6=%.2f kohms",R1*10^(-3));
printf("\nR3=R4=%.2f kohms",R4*10^(-3));
printf("\nC1=C2=%.2f nF",C1*10^9);
if ftf0>ftQ then
ft=ftf0;
else ft=ftQ
printf("\nGBP>=%.2f MHz",ft*10^(-6));
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