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//Example 4.7
clear;
clc;
f01=3460.05;
fz1=3600;
Q1=31.4;
f02=3745;
fz2=3600;
Q2=31.4;
f03=3600;
fz3=3600;
Q3=8.72;
//The answer of the Example 4.7 is not given in the textbook
//The filter is designed using three biquad sections, namely, a high pass notch, followed by a low pass notch, followed by a symmetric notch.
//Ist(High pass notch Biquad section)
C=10*10^(-9);
w01=2*%pi*f01;
wz1=2*%pi*fz1;
R1=1/(2*%pi*f01*C);
R11=Q1*R1;
R21=100*10^3;
R31=100*10^3;
R41num=R21*(w01^2);
R41den=Q1*abs((w01^2)-(wz1^2));
R41=R41num/R41den;
R51=R21;//as fz1<f01
Rex1=14.7*10^3;
Rex1pot=5*10^3;
//IInd Stage (low pass notch biquad stage)
w02=2*%pi*f02;
wz2=2*%pi*fz2;
R2=1/(2*%pi*f02*C);
R12=Q1*R2;
R22=100*10^3;
R32=100*10^3;
R42num=R22*(w02^2);
R42den=Q2*abs((w02^2)-(wz2^2));
R42=R42num/R42den;
R52=R22*((w02/wz2)^2);//as fz2>f02
Rex2=11.8*10^3;
Rex2pot=5*10^3;
//IIIrd Stage (Symmetric Notch Section)
L13=0.84304;
C13=0.62201;
CC130=C13/(2*%pi*f03);
CL130=L13/(2*%pi*f03);
C03=10*10^(-6);//Assumption
CC13=CC130*C03;
CL13=CL130*C03;
printf("Designed Chebyshev Band Reject Filter :");
printf("\nStage I(High pass notch Biquad section)");
printf("\nR=%.2f kohms",R1*10^(-3));
printf("\nR1=%.2f kohms",R11*10^(-3));
printf("\nR2=%.2f kohms",R21*10^(-3));
printf("\nR3=%.2f kohms",R31*10^(-3));
printf("\nR4=%.2f kohms",R41*10^(-3));
printf("\nR5=%.2f kohms",R51*10^(-3));
printf("\nC=%.2f nF",C*10^9);
printf("\n\nStage II(Low pass notch Biquad section)");
printf("\nR=%.2f kohms",R2*10^(-3));
printf("\nR1=%.2f kohms",R12*10^(-3));
printf("\nR2=%.2f kohms",R22*10^(-3));
printf("\nR3=%.2f kohms",R32*10^(-3));
printf("\nR4=%.2f kohms",R42*10^(-3));
printf("\nR5=%.2f kohms",R52*10^(-3));
printf("\nC=%.2f nF",C*10^9);
printf("\n\nStage III(Symmetric Notch Section)");
printf("\nC0=%.2f uF",C03*10^(6));
printf("\nCC1=%.2f pF",CC13*10^(12));
printf("\nCL1=%.2f pF",CL13*10^(12));
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