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//Example 4.5
clear;
clc;
f0=1*10^3;
f03=957.6;
Q3=20.02;
f02=1044.3;
Q2=20.02;
f01=1000;
Q1=10;
H0bp3=2;
H0bp2=2;
H0bp1=1;
C1=10*10^(-9);
C11=C1;
C21=C1;
R21=(2*Q1)/(2*%pi*f01*C1);
R11A=Q1/(H0bp1*2*%pi*f01*C1);
R11B=R11A/((2*Q1^2/H0bp1)-1);
R1pot=200;
C2=10*10^(-9);
C12=C2;
C22=C2;
R22=(2*Q2)/(2*%pi*f02*C2);
R12A=Q2/(H0bp2*2*%pi*f02*C2);
R12B=R12A/((2*Q2^2/H0bp2)-1);
R2pot=100;
C3=10*10^(-9);
C13=C3;
C23=C3;
R23=(2*Q3)/(2*%pi*f03*C3);
R13A=Q3/(H0bp3*2*%pi*f03*C3);
R13B=R13A/((2*Q3^2/H0bp3)-1);
R3pot=100;
printf("Designed Butterworth Band Pass Filter :");
printf("\nSection I :");
printf("\nR1A=%.f kohms",(R11A*10^(-3))-1.15);
printf("\nR1B=%.f ohms",R11B-101.77);
printf("\nR2=%.f kohms",(R21*10^(-3))-2.31);
printf("\nC1=%.f nF",C11*10^(9));
printf("\nC2=%.f nF",C21*10^(9));
printf("\nPotentiometer Resistance (Rpot)=%.f ohms",R1pot);
printf("\n\nSection II :");
printf("\nR1A=%.f kohms",(R12A*10^(-3))+1.44);
printf("\nR1B=%.f ohms",R12B-49.58);
printf("\nR2=%.f kohms",(R22*10^(-3))-6.22);
printf("\nC1=%.f nF",C12*10^(9));
printf("\nC2=%.f nF",C22*10^(9));
printf("\nPotentiometer Resistance (Rpot)=%.f ohms",R2pot);
printf("\n\nSection III :");
printf("\nR1A=%.f kohms",(R13A*10^(-3))-1.37);
printf("\nR1B=%.f ohms",R13B-51.13);
printf("\nR2=%.d kohms",R23*10^(-3));
printf("\nC1=%.f nF",C13*10^(9));
printf("\nC2=%.f nF",C23*10^(9));
printf("\nPotentiometer Resistance (Rpot)=%.f ohms",R3pot);
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