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//Example 3.9
clear;
clc;
//Applying Thevenin's theorem
//Anew=(R1B/(R1A+R1B))Aold and R1A || R1B =R1
AnewdB=0;
Anew=10^AnewdB;
C=10*10^(-9);
Aold=2.8;//Obtained from Example 3.8
RA=10*10^3;//Assumed value of RA
RB=17.8*10^3;
R1=15915.494;//obtained from Example 3.8
R2=R1;
R1A=R1*(Aold/Anew);
R1B=R1/(1-(Anew/Aold));
printf("Designed Second Order Low Pass Filter for 0dB dc gain :");
printf("\nR1A=%.2f kohms",R1A*10^(-3));
printf("\nR1B=%.2f kohms",R1B*10^(-3));
printf("\nR2=%.2f kohms",R2*10^(-3));
printf("\nRA=%.2f kohms",RA*10^(-3));
printf("\nRB=%.2f kohms",RB*10^(-3));
printf("\nC=%.2f nF",C*10^9);
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