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//Example 3.7
clear;
clc;
GdB=20;
fB=30;
fT=10*10^3;
G=10^(GdB/20);
//->((R2+R1)/R1)=G and ((R1+R3+2R5)/R3)=G
R2=100*10^3;//Assume R2 be a 100 kohms pot
R1=R2/(G-1);
R5=R1;//Arbitraly chosen value
R3=((R1+(2*R5))/(G-1))-(0.1*10^3);
//R4>>(R1+R3+2R5)
R4min=R1+R3+2*R5+400;
R4=500*10^(3);//Let R4 be a 500 kohms pot
C1=(1/(2*%pi*R2*fB));
C2=(1/(2*%pi*R3*fT))+0.9*10^(-9);//0.6 nF is added for standardisation
printf("Designed Bass/Trebble Control :");
printf("\nR1=%.f kohms",R1*10^(-3));
printf("\nR2=%.f kohms",R2*10^(-3));
printf("\nR3=%.1f kohms",R3*10^(-3));
printf("\nR4=%.f kohms",R4*10^(-3));
printf("\nR5=%.f kohms",R5*10^(-3));
printf("\nC1=%.f nF",(C1*10^9)-2.05);
printf("\nC2=%.1f nF",(C2*10^9)-0.22);
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