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//Example 3.17
clear;
clc;
f0=1*10^3;
Q=10;
HondB=0;
Hon=10^(HondB/20);
C=10*10^(-9);//Assuming C=10 nF
C1=C;
C2=C;
R3=10*10^3;
R4=R3/Hon;
R5=Hon*R4;
R2=(2*Q)/(2*%pi*f0*C);
R1A=Q/(Hon*2*%pi*f0*C);
R1B=R1A/((2*Q^2/Hon)-1);
printf("Designed Multiple Feedback Notch Filter :");
printf("\nR1A=%.2f kohms",R1A*10^(-3));
printf("\nR1B=%.2f ohms",R1B);
printf("\nR2=%.2f kohms",R2*10^(-3));
printf("\nR3=%.2f kohms",R3*10^(-3));
printf("\nR4=%.2f kohms",R4*10^(-3));
printf("\nR5=%.2f kohms",R5*10^(-3));
printf("\nC1=C2=%.2f nF",C*10^9);
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