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//Example 3.13(a)
clear;
clc;
C=10*10^(-9);//Assumed
C1=C;
C2=C;
f0=1*10^3;
BW=100;
R=(2^(1/2))/(2*%pi*f0*C);
R1=R;
R2=R;
R3=R;
Q=f0/BW;
K=4-((2^(1/2))/Q);
RA=10*10^3;
RB=(K-1)*RA;
RG=K/(4-K);
printf("Designed KRC Second Order Band Pass filter");
printf("\nR1=R2=R3=%.1f kohms",R*10^(-3));
printf("\nRA=%.2f kohms",RA*10^(-3));
printf("\nRB=%.2f kohms",RB*10^(-3));
printf("\nC1=C2=%.2f nF",C*10^9);
printf("\n\nResonance Gain=%.2f V/V",RG);
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