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clear;
clc;
// Illustration 7.2
// Page: 433
printf('Illustration 7.2 - Page: 433\n\n');
// solution
//*****Data*****//
// 'b'-solvent 'f'-feed 'r'-raffinate 'e'-extract 'c'-one of the // component in feed
F = 50; // [feed rate, kg/h]
S = 50; // [solvent rate, kg/h]
xcf = 0.6;
xbf = 0;
ycs = 0;
ybs = 1.0;
// The equilibrium data for this system can be obtained from Table 7.1 and // Figure 7.6
// Plot streams F (xcF = 0.6, xBF = 0.0) and S (yes = 0.0, yBs = 1.0). After // locating streams F and S, M is on the line FS; its exact location is found // by calculating xcm from
xcm = (F*xcf+S*ycs)/(F+S);
// From figure 7.8
xcr = 0.189;
xbr = 0.013;
yce = 0.334;
ybe = 0.648;
M = F+S; // [kg/h]
// From equation 7.8
E = M*(xcm-xcr)/(yce-xcr); // [kg/h]
R = M-E; // [kg/h]
printf("The extract and raffinate flow rates are %f kg/h and %f kg/h respectively.\n\n",E,R);
printf("The compositions when one equilibrium stage is used for the separation is %f and %f in raffinate phase for component b and c respectively and %f and %f in extract phase for component b and c respectively.\n\n",xcr,xbr,yce,ybe);
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