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//calculation of specific heat
clear;
clc;
printf("\t Example 6.7\n");
//for water
m=100;//mass, g
s=4.184;//specific heat, J/g C
deltaT=23.17-22.5;//change in temp., C
qH2O=m*s*deltaT;//heat gained by water, J
//for lead
qPb=-qH2O;//heat lost by lead, J
m=26.47;//mass, g
deltaT=23.17-89.98;//change in temp., C
s=qPb/(m*deltaT);//specific heat, J/g C
printf("\t the specific heat of lead is : %4.3f J/g C\n",s);
//End
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