881/CH8/EX8.4/exa8_4.sce


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clc;
//Example 8.4
//Page no 310


//solution

SN=38; //dB
In=-112; //dBm
FMi=17; //dB
NF=5; //dB

sn=SN-FMi+NF;

disp('dB',sn,"The receiver input S/N is ");

rs=In+sn;

disp('dBm',rs,"Therefore, the minimum receive signal level is ");