blob: 8f659237c4d8de5a25cddd938104a4edc91826c2 (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
|
clc
clear
printf("example 2.30 page number 83\n\n")
//to find the mixture composition
vapor_pressure=8 //in kPa
pressure=100 //in kPa
//part 1
volume=1 //in m3
volume_ethanol=volume*(vapor_pressure/pressure);
volume_air=1-volume_ethanol;
printf("volumetric composition:- \nair composition = %f\n ethanol compostion = %f",volume_air*100,volume_ethanol*100)
//part 2
molar_mass_ethanol=46;
molar_mass_air=28.9;
mass_ethanol=0.08*molar_mass_ethanol; //in kg
mass_air=0.92*molar_mass_air; //in kg
fraction_ethanol=(mass_ethanol*100)/(mass_air+mass_ethanol);
fraction_air=(mass_air*100)/(mass_air+mass_ethanol);
printf("\n\ncomposition by weight:-\nAir = %f Ethanol vapor = %f",fraction_air,fraction_ethanol)
//part 3
mixture_volume=22.3*(101.3/100)*(299/273); //in m3
weight_ethanol=mass_ethanol/mixture_volume;
printf("\n\nweight of ethanol/cubic meter = %f Kg",weight_ethanol)
//part 4
w_ethanol=mass_ethanol/mass_air;
printf("\n\nweight of ethanol/kg vapor free air = %f Kg",w_ethanol)
//part 5
moles_ethanol=0.08/0.92;
printf("\n\nkmol of ethanol per kmol of vapor free air = %f",moles_ethanol)
|
