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//Example 3.10
clc
clear
A = [1 1 1; 4 3 -1; 3 5 3];
n = length (A(1,:));
Aug = [A,eye(n,n)];
N = 1:n;
for i = 1:n
dummy1 = N;
dummy1(i) = [];
index(i,:) = dummy1;
end
// Forward Elimination
for j = 1:n
[dummy2,t] = max(abs(Aug(j:n,j)));
lrow = t+j-1;
Aug([j,lrow],:) = Aug([lrow,j],:);
Aug(j,:) = Aug(j,:) / Aug(j,j);
for i = index(j,:)
Aug(i,:) = Aug(i,:) - Aug(i,j) / Aug(j,j) * Aug(j,:);
end
end
Inv_A = Aug(:,n+1:2*n);
disp(Inv_A,"Inverse of A (A-1) = ")
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