758/CH8/EX8.1/Ex_8_1.sce


1
2
3
4
5
6
7
8
9
10

//Example 8.1
clc;clear;close;
s=poly(0,'s');
z=poly(0,'z');
T=1;
Hs=1/(s+2);
Hz=horner(Hs,(1-1/z)/T);
disp('Using Backward difference formula for derivative:')
disp(Hs,'H(s)=');
disp(Hz,'H(z)=');