blob: 0a926fd76d5305efa38ab6882482e3d8d6e7dab1 (
plain)
1
2
3
4
5
6
7
8
9
10
11
|
clc;
//page no 343
//problem no 10.12.1
p=10;t=0.3*10^-6;gm=2*10^-3;
q=1/p;f_max=q/(2*%pi*t);
Z2=p/gm;
R2=Z2;//Z2 is resistance
//Determination of equivalent tuning capacitance
C1=t/R2;
Ceq=gm*t;
disp('f',Ceq,'The equivaent tuning capacitance is');
|
