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(a)The exact moment of inertia of the rim considering difference of moment of inertia is
I=1/2*mo*ro2 - 1/2*mi*ri2
I=293 kgm2
(b)/the approximate moment of inertia, considering the rim as a thin ring is:
Iapprox=m*r2
Iapprox=288 kgm2
Percent error= 1.6
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