698/CH16/EX16.5/5_number_of_coils_helical_spring.txt


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C= D/d
D=9.6 mm

Wahl factor
K= ((4*C -1)/(4*C -1)) + (0.615/C)
	=1.10

F/y = dG/8*n*C^3
n=41.15 turns

F= 52.43 N

The deflection should be limited to 29.13 mm