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clc;
clear;
// To find the tempearure difference in the plane wall with heat sources
d1 = 0.55; // Inside diameter of copper wire
d2 = 0.8; // Outside diameter of copper wire
phi = 0.6; // Fraction of copper in wire
j = 1300; // Current density in conductors in amp/in^2
p = 9.5*10^(-6); // Specific resistance in ohm-in^2/ft
h = 4; // Heat transfer coefficient on both sides ofcoil
k = 0.2; // Thermal conductivity of coil in Btu/hr-ft-F
T0 = 70; // Temperature of air in degF
// Considering it as a plane wall with a thickness of 0.25 ft
b = 0.125; // half the thickness of wall in ft
l = 0.0625; // Distance between the two walls
q = j*j*p*phi*144*3.412; // Generation of heat in Btu/hr-ft-F
th0 = (4730*l*l/(2*k))+(4730*l/h); // Teperature difference in F
t0 = T0+th0; // Temperature at the center in F
printf("The temperature at the centre of the pool is %.1f degF \n",t0);
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