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//Problem 4.07:
//initializing the variables:
mdt1 = 1000; // in lb/min
mdt2 = 1000; // in lb/min
mdt3 = 200; // in lb/min
//calculation:
mdt5 = mdt1 + mdt2 - mdt3
mdt6 = mdt2
mdt = mdt5 - mdt6
printf("\n\nResult\n\n")
printf("\n amount of water lost by evaporation is %.0f lb/min",mdt)
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