2_9.sce « EX2.9 « CH2 « 671 - Scilab-TBC-Uploads/.git -

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//KCLs

A=[2,-1;-4,19]
V=inv(A)*[10;25]

Pc=1*V(1)
Iv=(5-V(2))/2 + (5-V(1))/5
Pv=5*Iv

disp(V)
disp(Pv,Pc)